Question

An object has an acceleration of 6.0 m/s/s. If the net force acting upon this object
were halved (1.e., one-half of the original net force), then its new acceleration would
be mss.​

Answer 1

Answer:

3 m/s

Explanation:

Force = mass X acceleration

Let F1 = m X a1 =  6m

F2 = F1/2 = 6m/2 = 3m

So acceleration = 3 m/s.

even it will be halved.

Answer 2

Explanation:

$\doublerightarrow$ $\sf Acceleration = 6m/s$

♦ Condition - If net force acting on it will be halved.

$\doublerightarrow$ $\large\boxed{F=m \times a}$

♦ Force applied is directly proportional to the acceleration produced and mass of the object.

If the net acceleration is asked -

Given - Force ' = $\sf \dfrac{Force}{2}$

Then , New Acceleration will also be halved .

$\therefore$ Acceleration = $\sf \dfrac{6}{2}$

$\large{\purple{\underline{\tt{Acceleration\:=\:3m/s}}}}$

$\rule{200}2$