an object having mass 150 gram and moving with a speed of 18 metre per second collides with the wall and return back along its original parts with the speed of 12 metre per second calculate the rate of change of momentum of this object given the object was in contact with the valve for 0.2 seconds
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Explanation:
Impulse=F×t= Change in Momentum
⇒ Change in Momentum =mv−mu=0.15(12)−0.15(−20)=4.8
⇒F×0.001=4.8
⇒F=4800N
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