an object having mass'm' is moving with a velocity of 5ms/1 has the kinetic energy of25j . kinetic energy of an object when velocity is increased by two times
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When object have velocity 5m/sec.
It has K.E. of 25 joules
so we get mass from following process
![K.E = \frac{1}{2} m ({5)}^{2} \\ 25 = \frac{1}{2} m \times 25 \\ m = 2kg K.E = \frac{1}{2} m ({5)}^{2} \\ 25 = \frac{1}{2} m \times 25 \\ m = 2kg](https://tex.z-dn.net/?f=K.E+%3D++%5Cfrac%7B1%7D%7B2%7D+m+%28%7B5%29%7D%5E%7B2%7D++%5C%5C+25+%3D++%5Cfrac%7B1%7D%7B2%7D+m+%5Ctimes+25+%5C%5C+m+%3D+2kg)
Now new kinetic energy when velocity doubles means v=10m/s
![K.E. = \frac{1}{2} (2) {(10)}^{2} \\ 100joules K.E. = \frac{1}{2} (2) {(10)}^{2} \\ 100joules](https://tex.z-dn.net/?f=K.E.+%3D++%5Cfrac%7B1%7D%7B2%7D+%282%29+%7B%2810%29%7D%5E%7B2%7D++%5C%5C+100joules)
New kinetic energy will be 100 joules.
It has K.E. of 25 joules
so we get mass from following process
Now new kinetic energy when velocity doubles means v=10m/s
New kinetic energy will be 100 joules.
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The mass of the object, m = m kg
The speed of the object, v = 5 m/s
The Kinetic Energy, K.E = 25 J
We know that ,
From this ,,,
Kinetic Energy ,K.E = 1/2 × m× (5)^2
25 = 1/2 × m × 25
m = 2 kg
(i) Now the Velocity of the object is doubled,,
v2 = 2v1
= 2( 5)
v2 = 10 m/s
Kinetic Energy, K.E = 1/2 × m × (v2)^2
= 1/2 × 2 × 10^2
= 100 J
The Kinetic Energy is 100 J.
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