Question

An object in shm oscillates with a period of 4.0s and an amplitude of 17 cm . How long does the object takes to move from 0 to 5.2 cm

Answer 1

# Answer- 0.2s

# Explanation-

# Given=

T=4s

A=17cm

x=5.2cm

# Solution

x = Asin(wt)

5.2 = 17sin(wt)

But

w=2πf

w=2π/T

w=2π/4

w=π/2

Hence

sin(πt/2)=0.3058

πt/2=17.81°

t=17.81/90

t=0.197s.

Approx t=0.2s