Question

An object in simple harmonic motion obeys the following position versus time equation:

y = (0.60 m) sin (π/4 t). What is the maximum speed of the object?

Answer 1

Answer:

See below.

Explanation:

The given SHM is,

$y=( 0.6 \ m) \ sin( \frac{ \pi}{ 4 } t )$

The maximum speed is given by,

$v_{max} = A \ \omega = 0.6 \times \frac{\pi}{ 4 } = 0.471 \ m/s$