Question

find the maximum number of emission lines, when excited electron of hydrogen atom in n=6 drops to n=1 (No. of emission lines can be found using formula,( n2-n1)(n2-n1+1)/2.(n2=6,n1=1)​

Answer 1

Answer:

15 lines

Explanation:

no of emission lines= ∑n2₋n1

• so, ∑6-1=∑5
• = 5+4+3+2+1
• =15 lines