An object is 5 cm high is placed at a distance of 10 cm from a concave mirror of radius of curvature 30 cm. Find the size of the image.
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Given :-
Object distance (u) = -10cm
Radius (R) = 30cm
Height of object (h) = 5cm
Size of image = ?
Also,
Focal length (F) = R/2
= 30/2
= -15cm
Solution :-
Mirror formula = 1/v +1/u = 1/f
Or,
1/v = 1/u - 1/f
1/v = -1/5 - (-1/15)
1/v = -1/5 + 1/15
1/v = (-3 + 1)/15
1/v = -2/15
v = -7.5 cm
Magnification = -v/u
= -(-7.5)/(-5)
= -(7.5)/5
= -1.5 cm
Also, Magnification = h'/h
h' = size of image
h = size of object
M = -1.5
-1.5 = h'/5
h' = -1.5 x 5
h' = -7.5
(i) Size of image is 7.5cm.
(ii) As M ∠ 0, image is magnified and inverted.
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