An object is allowed to fall freely from a cliff. When it travels a distance 'h', its velocity is v. Hence, in traveking what amiunt of furthet distance will its velocity become 2v? Quality answer needed asap.
Answers
Answer:3h
Explanation:
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Answer: h’= 3h
Concept: Free fall
Given: V0=0, d= h
To Find: Distance
On the basis of final velocity, initial velocity, and gravitation.
We can use the formula for uniformly accelerated motion
i.e. V^2 = U^2 + 2gh
where v is the end velocity, u is the beginning velocity, g is the gravitational acceleration, and h is the height.
The equation changes to V^2=2gh when u=0 (for an object starting at rest).
Which becomes h= V^2/2g …………………. (1)
As per the given problem, the velocity of an object at height h is V0= V and the velocity of an object at height h’ will be 2V
(2V)^2- (V)^2= 2gh’
4V^2- V^2= 2gh’
h’= 3V^2/ 2g ………………… (2)
Dividing equation (2) by (1)
We get
h’/h= 3V^2/2g x V^2/2g
h’/h= 3
h’= 3h
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