If the displacement s of a particle is given by s = 8t^2 + 3t - 5, where s is given in cm and t in s, what is the initial velocity of the particl
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Initial velocity is defined as derivative of displacement at t= 0
ds/dt will be 16t+3 i.e v=16t+3
Now initial velocity means t=0
As a result v will be 3 cm/sec
ds/dt will be 16t+3 i.e v=16t+3
Now initial velocity means t=0
As a result v will be 3 cm/sec
shreyashdonal9009:
what anytime
we know that if a body starts from rest or drops we take inital velocity =0
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if acceleration depends on time than it is non uniform
or uniform
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initial velocity is 3 m/s
hope it helps you out
hope it helps you out
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bhai t=0 kaise le liya
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