Question

an object is displaced 20 cm on applying force of 5 N at an angle of 30° with a horizontal surface. calculate the work done. given cos 30° = ¾. root 3= 1.73​

Answer 1

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Answer 2

Answer:

F=10N,S=2m,θ=60

0

So, Work=F×Scosθ=10×2cos60

0

=10×2×

2

1

=10J

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