Question

An object is droped from a height of 200m.calculate the time to reached the ground and with what velocity it strikes the ground​

Answer 1

$\huge{\underline{\underline{\boxed{\sf{\purple{Answer : }}}}}}$

Distance (s)  = 20 m

Initial velocity = 0 m/s

g = 10 m/s^2

$\small \underline {\sf{For \ calculating \ time}}$:

v^2 = u^2+2as

v^2 = 02+2×10×20

v^2= 400

v =√400

v = 20m/s

$\small \underline {\sf{ By \ using \ the \ formula}}$:

V = u+at

20 = 0+10×t

t = 20/10

t =2 sec

• $\small \underline {\sf{ the \ stone \ will \ hit \ the \ ground \ with \ a \ velocity }}$$\small \underline {\sf{of \  20 m/s \  in \ sec }}$

Answer 2

Answer:

Distance (s) = 20 m

Initial velocity = 0 m/s

g = 10 m/s^2

\small \underline {\sf{For \ calculating \ time}}

For calculating time

:

v^2 = u^2+2as

v^2 = 02+2×10×20

v^2= 400

v =√400

v = 20m/s

\small \underline {\sf{ By \ using \ the \ formula}}

By using the formula

:

V = u+at

20 = 0+10×t

t = 20/10

t =2 sec

• \small \underline {\sf{ the \ stone \ will \ hit \ the \ ground \ with \ a \ velocity }}

the stone will hit the ground with a velocity

\small \underline {\sf{of \ 20 m/s \ in \ sec }}

of 20 m/s in sec