An object is dropped from a height of 120 m. The acceleration of the object is 10 ms-2 downwards. Find the distance travelled and velocity after 3 s ???
RickHazra99:
Someone answer this pls
i have been waiting for a long time
can some one write it pls
Answers
Answered by
7
Heya!!
---------------------------
Since S (distance travelled) = ut+1/2gt^2
= 0*3 + 1/2 * 10 * 3*3
= 5*3*3
= 45 m.
Since v = u + at
=) v = 0 + 10*3
=) v = 30 m/s
Hope it helps uh :)
---------------------------
Since S (distance travelled) = ut+1/2gt^2
= 0*3 + 1/2 * 10 * 3*3
= 5*3*3
= 45 m.
Since v = u + at
=) v = 0 + 10*3
=) v = 30 m/s
Hope it helps uh :)
thank you so much
Similar questions