Question

An object is dropped from a height of 120 the acceleration of the object is 10 metre per second downwards find the distance travelled by the object after 1 second to second 3 second what is the final velocity of the object after 3 seconds

Answer 1

QUESTION:

An object is dropped from a height of 120 the acceleration of the object is 10 metre per second downwards find the distance travelled by the object after 1 second to second 3 second what is the final velocity of the object after 3 seconds.

ANSWER:

1.) distance travelled by the object from 1 to 2 seconds = 20m

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2.) the final velocity of the object after 3 seconds = 30 m/s

Explanation:

given that,

An object is dropped from a height of

120 m

so,

here initial velocity = 0 [since was in rest]

height = 120 m

given,

gravitational acceleration = 10 m/s²

to find,

1.) distance travelled by the object after 1 second to second 3

let final velocity be v

here,

we have ,

time(t) = 2 seconds ,

height(h) = h

initial velocity(u) = 0

final velocity = v

gravitational acceleration = 10 m/s²

by the motion formulae of gravitation ,

h = ut + 1/2gt²

now,

putting the values,

h = (0)(2) + 1/2(10)(2)²

h = 40/2

h = 20 m

so,

distance travelled by the object from 1 to 2 seconds = 20 m

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2.)  the final velocity of the object after 3 seconds

here,

time = 3 seconds

here,

height(h) = h

initial velocity = 0

let the final velocity after 3 seconds be v

gravitational acceleration(g) = 10 m/s²

by the motion formulae of gravitation

h = ut + (1/2)gt²

h = (0)(3) + (1/2)(10)(3)²

h = 90/2

h = 90 m

so,

body will 90 m far from the initial point.

now,

velocity = distance/time taken

distance = 90 m

time taken = 3 seconda

putting the values

velocity = 90/3

velocity = 30 m/s

so,

the final velocity of the object after 3 seconds = 30 m/s