an object is dropped from a height of 80 m. it wil remain in air for time (take g =10m/s square
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Answered by
1
Hi friend,
We know that,
S= ut +1/2 at²
Initial velocity =0.
T² = 2s/a
t²= 2×80/10
t= 4 secs.
Hope this helped you a little!!!
We know that,
S= ut +1/2 at²
Initial velocity =0.
T² = 2s/a
t²= 2×80/10
t= 4 secs.
Hope this helped you a little!!!
Answered by
0
We use the formula of kinematics here.Also since the time can't be negative the ans is positive 4.
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