An object is dropped from a height of 80 m. It will remain in air for time [Take g = 10 m/s2] with formula
Answers
Answered by
3
Use the formula
s = ut + 1/2gt2 ( it is t square)
Where s = 80
u = 0
g = + 10
s = ut + 1/2gt2 ( it is t square)
Where s = 80
u = 0
g = + 10
Answered by
7
Hi friend,
We know that
S= ut+1/2 at²
Since initial velocity is zero,ut =0.
S= 1/2 at²
t² = 2S/a
t² = 2×80/10
t= 4secs.
Hope this helped you a little!!!!
We know that
S= ut+1/2 at²
Since initial velocity is zero,ut =0.
S= 1/2 at²
t² = 2S/a
t² = 2×80/10
t= 4secs.
Hope this helped you a little!!!!
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