Question

an object is dropped from a height of 80m time taken for the object to reach the ground is? (g=10m/s^2)

Answer 1

Answer:

t=4 seconds

Explanation:

Given :

Height of the building = s = 80 metres

Acceleration due to gravity = a = 10 m/s²

Initial velocity = u = 0 m/s

To find :

Time taken by the object to reach the ground

Using the second equation of motion :

S=ut+½×at²

80=0×t+½×10×t²

80=5t²

t²=80/5

t²=16

t=4 seconds

The time taken by the object to reach the ground is equal to 4 seconds

Answer 2

✯✯ QUESTION ✯✯

An object is dropped from a height of 80m time taken for the object to reach the ground is? (g=10m/s^2)?

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✰✰ ANSWER ✰✰

$\implies\tt{Initial\:velocity(u)=0m/s}$

$\implies\tt{Height(s)=80m}$

$\implies\tt{Acceleration(a)=10m/s}$

$\implies\tt{Time\:Taken(t)=?}$

➥Using 2nd Equation of Motion : -

$\implies\tt{\small{\boxed{\bold{\bold{\red{\sf{s=ut+\dfrac{1}{2}{at}^{2}}}}}}}}$

➥Putting Values : -

$\implies\tt{80=(0)t+\dfrac{1}{2}(10){(t)}^{2}}$

$\implies\tt{80=\dfrac{1}{\cancel{2}}\times{\cancel{10}}\times{{t}^{2}}}$

$\implies\tt{80={5t}^{2}}$

$\implies\tt{{t}^{2}=\cancel\dfrac{80}{5}}$

$\implies\tt{{t}^{2}=16}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{t}\orange{=}\purple{4\:sec.}}}$

☛So the Time Taken by the object is 4 seconds..