Question

An object is dropped from rest at a height of 150 m and simultaneously another object is
dropped from rest at a height 100 m. What is the difference in their heights after 2s if both the
objects drop with same acceleration? How does the difference in heights vary with times?​

Answer 1

for Ist object. u =0. t=2sec

the object is 150m abobe the ground

a =g= 10 (9.8)

s=ut+1/2at^2

s=0×2+1/2×10×2×2

s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 150-20=130M

for IInd object. u =0. t=2sec

a =g= 10 (9.8)

the object is 100m abobe the ground

a =g= 10 (9.8)

s=ut+1/2at^2

s=0×2+1/2×10×2×2

s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 100-20=80M

THE DISTANCE BETWEEN THE OBJECTS AFTER 2 SEC

===130-80=50