Question

if the angel of quadrilateral are x °,(2x+13)°,(3x+10)°and(x-6)°,then find the angles.​

Answer 1

Answer:

x+2x+13+3x+10+x-6=360(sum of angles of quadrilateral )

7x+17=360

x=343/7

x=49

Answer 2

x•+(2x+13)°+(3x+10)°+(x-6)° = 360°

Bcz. sum of all angles of a quadrilateral is equal to 360°

7x+17 = 360°

7 x =360•-17°

x = 343/7

x. =49°

hope u get ur ans..