Question

an object is dropped from rest at a height of 150 M and simultaneously another object is dropped from rest at a height 100m what is the difference in their height after 2 seconds if both the objects with same acceleration how does the difference in Heights vary with time

Answer 1

s1=1/2*gt2
=1/2*10*4
=20 m from height
=130m above from ground.

s2=1/2*10*4
=20m from drop
=80m above ground.
s1-s2=130-80=50

therefore,diff b/w third heigh after 2 s =50 m