Question

An object is dropped from rest at a height of 150m and simultaneously another object is dropped from rest at a height 100m. What is their difference in their heights after 2 seconds if both the objects drop with same acceleration? How does the difference in heights vary with time?

Answer 1

The two objects fall with same acceleration simultaneously. Hence, after 2 seconds the difference in their heights will still be 50 m.



Hence, the height of first object after 2 seconds is 130 m.

Similarly the height of second object is



Hence, the height of second object after 2 seconds is 80 m.

So, the difference is same, i.e. 50 m.

Hence, we can conclude that the difference in height of the two objects does not depend on time and will always be same.

Answer 2

The two objects fall with same acceleration simultaneously. Hence, after 2 seconds the difference in their heights will still be 50 m.  d1=h1-s1
d1=150-1/2at²
=150-1/2*10*4
=150-20=130mHence, the height of first object after 2 seconds is 130 m. Similarly the height of second object is d2=h2-s2d2=100-1/2at²
=100-1/2*10*4
=100-20=80m Hence, the height of second object after 2 seconds is 80 m. So, the difference is same, i.e. 50 m.