Question

An object is dropped from rest calculate it's velocity after 2.5s where acceleration due to gravity is3.8m/second square​

Answer 1

Explanation:

v=u+at-----(Newton's equation of motion)

{v is final velocity, u is initial velocity, a is acceleration due to gravity and t is time}

v=0+3.8*2.5----(u=0 since it was initially at rest)

v=9.5m/s