Question

An object is dropped from the rest at a height of 150 m and simultaneously

another object is dropped from the rest 100 m. What is the difference in their

heights after 2 seconds if both objects are dropped at the same

acceleration? How does the difference in heights vary with time?​

Answer 1

Answer:

zero

Explanation:

Initial difference in height = ( 150 - 100) m = 50m

we know that , by second equation of kinematics , s = ut + ½ at ²

considering g = 10m/s

Distance travelled by first body in 2s

= H1 = 0 + ( ½ ) g ( 2 ) ² = 2g = 2 × 10 = 20m

Distance travelled by another body in 2s

= H2 = 0 + ( ½ ) g ( 2 ) ² = 2 × 10 = 20m

After 2s , height at which the body first will be

= H1 = 150-20 = 130m

After 2s , height at which the second body will be = H2 = 100 - 20 = 80m

Thus, after 2s , difference in height

= ( 130 - 80 )

= 50m = initial difference in height

Thus , difference in height does not vary with time. so , the answer is zero .

Hope it helps you