Question

An object is dropped in an unknown planet from height 50m , it reaches the ground in 2 s . The acceleration due to gravity is what

Answer 1

Answer: The acceleration due to gravity is $a = 25m/s^{2}$

Explanation:

Given that,

Distance s = 50 m

Initial velocity u = 0

Using equation of motion

$s = ut+\dfrac{1}{2}at^{2}$

$50 m= 0+\dfrac{1}{2}\times a\times 4s$

$a = 25m/s^{2}$

Hence, the acceleration due to gravity is $a = 25m/s^{2}$

Answer 2

"Given that,

Distance s = 50 m

Initial velocity u = 0

Time t = 2 s

Using equation of motion,

$s=ut+\frac { 1 }{ 2 } at^{ 2 }$

$\Rightarrow 50=0+\frac { 1 }{ 2 } \times a\times 2\times 2$

$\Rightarrow 50=a\times 2$

$\Rightarrow a=25\frac { m }{ s^{ 2 } }$

Hence, the acceleration due to gravity is $a=25\frac { m }{ s^{ 2 } }$ ."