An object is executing uniform circular motion with an angular speed of π/12 radian per second. At t = 0 the object starts at an angle Θ = 0 What is the angular displacement of the particle after 4 s ?
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In uniform circular motion,
angular velocity remains constant .so, angular acceleration is always zero.
∴ to find angular distance , we have to use formula, Θ = ωt
Given, ω = π/12 rad/s and t = 4 sec
∴ Θ = π/12 × 4 = π/3 rad
Hence, angular distance = π/3 rad
angular velocity remains constant .so, angular acceleration is always zero.
∴ to find angular distance , we have to use formula, Θ = ωt
Given, ω = π/12 rad/s and t = 4 sec
∴ Θ = π/12 × 4 = π/3 rad
Hence, angular distance = π/3 rad
yamini47:
wrong
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Displacement = Pi divided by 12 is equal to 30.
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