Question

If an object is thrown horizontally with an initial speed 10 m s⁻¹ from the top of a building of height 100 m. what is the horizontal distance covered by the particle?

Answer 1

This is the case of horizontal projectile.
Given, initial velocity , u = 20 m/s
height , h = 100m
use the formula,
Horizontal range , X = u√(2h/g)
So, X = 20 × √{2 × 100/10}
X = 20 × √20 m

Hence, horizontal distance covered by object is 20√20 m

Answer 2

Answer:

Explanation:

This is the case of horizontal projectile.

Given, initial velocity , u = 20 m/s

height , h = 100m

use the formula,

Horizontal range , X = u√(2h/g)

So, X = 20 × √{2 × 100/10}

X = 20 × √20 m

Hence, horizontal distance covered by object is 20√20 m