Question

An object is in equilibrium under four concurrent forces in the direction shown in figure. The magnitude F1 and F2 are-
(A) zero: 4√3N
(B) 4√3 N; zero
(C)4√3 N; 4√3N
(D) zero, zero​

Answer 1

Answer:

ans is A. I hope it's helpful for you

Answer 2

(A)0,$4\sqrt3 N$

Explanation:

$F_3=4 N$

$F_4=4 N$

Angle between F3 and F4 =60 degree

Angle between F1 and F3=30 degree

According to given figure

$4sin60^{\circ}+F_1=F_2sin30^{\circ}$

$4\times \frac{\sqrt 3}{2}+F_1=F_2\times \frac{1}{2}$

$2\sqrt 3+F_1=\frac{F_2}{2}$

$F_2=4\sqrt 3+2F_1$...(1)

$F_2cos30=4+4cos60$

$F_2\times \frac{\sqrt 3}{2}=4+4\times \frac{1}{2}$

$F_2\times \frac{\sqrt 3}{2}=4+2=6$

$F_2=6\times \frac{2}{\sqrt 3}=4\sqrt 3$ N

Using the value of F2

$4\sqrt 3=4\sqrt3+2F_1$

$2F_1=4\sqrt3-4\sqrt 3=0$

$F_1=0$

Hence, option A is true.

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