Question

An object is in the shape of a right circular cylinder with a hemisphere on one end and a cone on the other. The height and radius of the cylindrical part are 13 cm and 5 cm respectively. The radii of the hemispherical and conical parts are the same as that of the cylindrical part. Calculate the surface area of the object if the height of the conical part is 12 cm.​

Answer 1

Answer:

770 cm²(approximately)

Step-by-step explanation:

Total height= 30cm

height of cylinder=13cm

height of cone=30-18 (radius of hemisphere=height)

therefore height of cone= 12cm

C.S.A. of hemisphere:

2 × 22/7 × 5²2

=157.14 cm²

C.S.A. of cylinder:

2 × 22/7 × 5 ×13

=408.571 cm^2

C.S.A of cone :

22/7 × 5 ×13

=204.28

Adding all C.S.As we get

408.57

204.28

+157.14

=769.99m^2 [Ans. =Surface area of toy]

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\mathcal\purple{Solution:-}$

⛄ Answer:-

☞ Surface area of the given object= 770 cm².

⛄ Step-by-step explanation:-

[..Have a glimpse at the attachment provided above..]

⏩ Let r cm be the radius and h cm the height of the cylindrical part. Then,

r= 5 cm and h= 13 cm.

Clearly, radii of the spherical part and base of the conical part are also r cm.

Now, let h1 cm be the height, l cm be the slant height of the conical part. Then,

l² = r² + h1²

=> l = √r² + h1²

=> l= √5² + 12²

=> l= 13 cm [Since h1 = 12 cm, r= 5cm]

Now,

Surface area of the object = CSA of the cylindrical part + CSA of the hemispherical part + CSA of the conical part.

= (2πrh + 2πr² + πrl) cm²

= πr (2h + 2r + l) cm²

= 22/7 × 5 × (2 × 13 + 2 × 5 + 13) cm²

= 22/7 × 5 × 49 cm² = 770 cm²

___________________________________

✔✔✔✔✔✔✔✔✔

Hope it helps...❣❣❣

⭐❤✨♥⭐❤✨♥⭐

Be Brainly....✌✌✌

♣ WALKER ♠