Physics, asked by graceland702, 6 months ago

An object is initially moving at an unknown velocity. It accelerates at a rate of 2.0 m/s² to a new velocity of 45 m/s in 10 s. What was the initial velocity?

Answers

Answered by Bᴇʏᴏɴᴅᴇʀ
55

Answer:-

\red{\bigstar} Initial velocity \large\leadsto\boxed{\rm\green{25 \: m/s}}

Given:-

  • Acceleration = 2 m/
  • Final velocity = 45 m/s
  • Time = 10 sec.

To Find:-

  • Initial velocity = ?

Solution:-

Initial velocity:-

We know,

First Equation of motion:-

\blue{\bigstar} \large\underline{\boxed{\bf\pink{v = u + at}}}

where,

  • v = final velocity
  • u = initial velocity
  • a = acceleration
  • t = time taken

Substituting in the values:-

\sf 45 = u + 2 \times 10

\sf 45 = u + 20

\sf u = 45 - 20

\bf\red{u = 25 \: m/s}

Therefore, the initial velocity is 25 m/s.

Answered by BrainlyHero420
126

Answer:

✯ Given :-

  • An object is initially moving at an unknown velocity. It's accelerates at a rate of 2.0 m/s² to a new velocity of 45 m/s in 10 secs.

✯ To Find :-

  • What is the initial velocity.

✯ Formula Used :-

\boxed{\bold{\large{✮\: v\: =\: u\: +\: at\: ✮}}}

✯ Solution :-

Given :

  • Final velocity (v) = 45 m/s
  • Acceleration (a) = 2 m/
  • Time (t) = 10 secs

According to the question by using the formula we get,

45 = u + 2 × 10

45 = u + 20

u = 45 - 20

u = 25 m/s

\therefore The initial velocity is 25 m/s .

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Extra Information

1st equation of motion :-

\large\purple{\underline{{\boxed{\textbf{v\: =\: u\: +\: at}}}}}

where,

  • v = Final velocity
  • u = Initial velocity
  • a = Acceleration
  • t = Time taken

2nd equation of motion :-

\large\green{\underline{{\boxed{\textbf{s\: =\: ut\: +\: ½\: at²}}}}}

where,

  • s = Distance covered
  • u = Initial velocity
  • t = Time taken

3rd equation of motion :-

\large\red{\underline{{\boxed{\textbf{v²\: -\: u²\: =\: 2as}}}}}

where,

  • v = Final velocity
  • u = Initial velocity
  • a = Acceleration
  • s = Distance covered

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