Question

an object is kept at a distance of 5 centimetre in front of convex mirror of the focal length 10cm calculation the positive and magnification of image of the state of nature

Answer 1

Given -
u = -5 cm
f = + 10 cm
v = ?
we know -
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \\ = > \frac{1}{v} + \frac{1}{ - 5} = \frac{1}{10} \\ = > \frac{1}{v} = \frac{1}{10} + \frac{1}{5} \\ = > v = + 10$
since the image is +ve , virtual , erected ,

magnification = h'/h = v/u ( since the image is virtual therefore we use +ve sign)

=> h'/h = 10/5

=> h'/h = 2/1
therefore , h' = 2m and h = 1 m
Magnified image is formed

hope this helps u !!!