Question

Seven years ago Stephen's age was five times the square of Riya's age'3 years hence Riya's age will be 2 fifth of Stephen's age. find their present ages.

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Answer 1

Seven years ago, lLet Swati
age be X years
Stephen's age =5x2 years
Riay present age =x+7 years
Varun’s present age=5x2+7 years
It is given that three years hence riay's age will be 2/5 of stephen’s age

x+10=2/5(5x2=10)
=x+10=2x2+4
=2x2-x-6=0
=2x(x-2)+3(x-2)=0
=(2x+3)(x-2)=0
=x-2=0
=x=2
Hence Riya's present age = (2 + 7) years = 9 years
Stephen's’s present age= (5*x2+7)years = 27 yand ears

Answer 2

Answer:

Step-by-step explanation:

Let seven years, age of Swati was x years and age of Varun was 5x² years

Present age of Swati = ( x + 7 ) years

Present age of Varun = ( 5x² + 7 ) years

Given, after 3 years swati's age will be 2 / 5 of Varun's age.

Age of Swati after 3 years = ( x + 7 + 3 ) years = ( x + 10 ) years

Age of Varun after 3 years = ( 5x² + 7 + 3 ) years = ( 5x² + 10 ) years

Given, age of Swati after 3 years = age of varun after 3 years

( x + 10 ) = 2 / 5 × ( 5x² + 10 )

( x + 10 ) = 2( x² + 2 )

x + 10 = 2x² + 4

2x² - x + 4 - 10 = 0

2x² - x - 6 = 0

2x² - 4x + 3x - 6 = 0

2x( x - 2 ) + 3( x - 2 ) = 0

x = 2 [ Age can't be negative ]

Therefore,

present age of Swati = ( 2 + 7 ) = 9 years

present age of Varun = 5(2)²+7=27 years

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