an object is kept at a distance of 5 cm in front of convex mirror of focal length 10 centimetre calculate the position and nature of image formed
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Given:
⇒Object distance, U= -5cm (to the left of convex mirror)
⇒ Focal length, f= 10cm (convex mirror)
To find:
⇒ Image distance, V=?
Solution:
By using the mirror formula, 1/f= 1/v + 1/u we get,
⇒ 1/v + 1/-5 = 1/10
⇒ 1/v = 1/10 + 1/5
⇒ 1/v = 3/10
⇒ v = 10/3
⇒ v = +3.33cm
Position of the image is at distance of 3.33cm from the convex mirror on its right side (behind the mirror). Since the image is formed behind the convex mirror, therefore nature of the image is Virtual and Erect.
:)
⇒Object distance, U= -5cm (to the left of convex mirror)
⇒ Focal length, f= 10cm (convex mirror)
To find:
⇒ Image distance, V=?
Solution:
By using the mirror formula, 1/f= 1/v + 1/u we get,
⇒ 1/v + 1/-5 = 1/10
⇒ 1/v = 1/10 + 1/5
⇒ 1/v = 3/10
⇒ v = 10/3
⇒ v = +3.33cm
Position of the image is at distance of 3.33cm from the convex mirror on its right side (behind the mirror). Since the image is formed behind the convex mirror, therefore nature of the image is Virtual and Erect.
:)
Answered by
3
Answer: The position of the image is 3.33 cm behind the convex mirror.
The image is virtual and erect.
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