Question

An object is launched into the air from the ground and its height is given by
h = – 16t2 + 176t, where h is the object’s height in feet, after t seconds.
1) Find the time required for the object to hit the ground

Answer 1

Step-by-step explanation:

An object is launched from the ground. The object’s height, in feet, can be described by the quadratic function h(t) = 80t – 16t2, where t is the time, in seconds, since the object was launched.

Since we want to know how much time elapsed since the object was launched until it ht the ground. At the ground, the height is 0.

Therefore the equation h(t) = 80t – 16t2 becomes 0= 80t – 16t2

Solving the equation for t gives 80t =16t2 or 16t=80 or t=5sec

The object hits the ground 5 seconds after it is launched.