Question

An object is moving with a velocity 10m/s comes to rest after 5 sec.
what will be the acceleration... help plz?

Answer 1

Answer:

acceleration = -2m/s^2

Or retardation = 2m/s^2

Explanation:

uniform velocity (u) = 10m/s

then, object comes to rest

so, final velocity (v) = 0m/s

and time = 5 sec.

•°• Acceleration = (v-u) / t

=> (0 - 10) / 5 = -10/5 = -2m/s^2

or Retardation = 2m/s^2

hope it helps.

please mark it as brainliest.

Answer 2

Answer:

-2 m/s²

Explanation:

Given:

Initial velocity = 10 m/s (i)

Final velocity = 0 m/s (v)

Time = 5 sec (t)

To find:

Acceleration (a)

Acceleration is nothing but the rate of change of the velocity

Formula for acceleration is given by:

$Acceleration = \frac{Final \ velocity-initial \ velocity}{time}$

$Acceleration = \frac{v-u}{t}$

Substituting these values, we get:

$a = \frac{0-10}{5}$

$a=\frac{-10}{5}$

$a= -2m/s^{2}$

The acceleration of the object is equal to -2 m/s²