Question

AN OBJECT IS MOVING WITH A VELOCITY OF 5M/S.ITS VELOCITY CHANGES TO 13 M/S IN 4 SECONDS. CALCULATE THE ACCELARTION

Answer 1

Provided that:

• Initial velocity = 5 m/s
• Final velocity = 13 m/s
• Time = 4 seconds

To calculate:

• The acceleration

Solution:

• The acceleration = 2 m/s sq.

Using concept:

• Acceleration formula

Using formula:

• ${\small{\underline{\boxed{\sf{a \: = \dfrac{v-u}{t}}}}}}$

Where, a denotes acceleration, v denotes final velocity, u denotes initial velocity and t denotes time taken

Required solution:

$:\implies \sf Acceleration \: = \dfrac{Change \: in \: velocity}{Time} \\ \\ :\implies \sf a \: = \dfrac{v-u}{t} \\ \\ :\implies \sf a \: = \dfrac{13-5}{4} \\ \\ :\implies \sf a \: = \dfrac{8}{4} \\ \\ :\implies \sf a \: = 2 \: ms^{-2} \\ \\ :\implies \sf Acceleration \: = 2 \: ms^{-2}$

Answer 2

Answer:-

• Initial velocity=u=5m/s
• Final velocity=v=13m/s
• Time=4s

We know that

$\boxed{\sf Acceleration=\dfrac{v-u}{t}}$

$\\ \sf{:}\longrightarrow Acceleration=\dfrac{13-5}{4}$

$\\ \sf{:}\longrightarrow Acceleration=\dfrac{8}{2}$

$\\ \sf{:}\longrightarrow Acceleration=4m/s^2$