an object is moving with initial velocity 20 m per second after 40 minutes it velocity became 60 M per second calculate acceleration and distance travelled by object in given time interval
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Time=40×60 sec.=2400 sec.
Acceleration=(v-u)/t=(60-20)/2400
=0.02m/sec^2.(approx)
Dist. Travelled=s.
v^2=u^2+2as
(60)^2=(20)^2+2×0.02×s
Or, 0.04s=3600-400
Or, s= 3200/0.04 =8×10^4 m. =80000m.
Hope it helps and please mark brainliest if pleased.
Acceleration=(v-u)/t=(60-20)/2400
=0.02m/sec^2.(approx)
Dist. Travelled=s.
v^2=u^2+2as
(60)^2=(20)^2+2×0.02×s
Or, 0.04s=3600-400
Or, s= 3200/0.04 =8×10^4 m. =80000m.
Hope it helps and please mark brainliest if pleased.
ishanaghosh:
If you have not studied yet, you will study soon the process of approximation.
My pleasure.
in which class you study
I asked first.
in which class
As i asked first, its only fitting that you answer first. Whatever, class 9.
You??
9 i also but you are intelligent
Thanks mate.
your welcome
Answered by
1
acceleration (a) =final velocity (v) - initial velocity (u) / time. =60-20/40*60 ms-2. Distance =ut+at^2/2
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