Question

An object is moving with uniform acceleration.Its velocity after 5s is 25m/s and after 8s is 34m/s.Find the distance travelled by the object in 12th second.

Answer 1

let Acc. be A
intial velocity be U
final velocity be V

then V = U+At
25= U + A5

Also, V = U* + At
34 = 25 + A3
A = 3m/S^2

Then we get U = 10m/s

Distance travelled in 12th sec. = (Distance travelled by body in 12sec) - (Distance travelled by body in 11sec)

= 336 - 291.5 = 44.5M