Question

An object is placed (1) asymmetrically (2) symmetrically, between two plane mirrors inclined at an angle of 50°. Find the number of images formed

Answer 1

Hi user!

For two mirrors kept at an angle x, the number of images n is determined by the formula 360/x.

If n turns out to be odd,
We have the following two cases:
Asymmetrically
--------------------
Number of images=n
Symmetrically
------------------
Number of images=n-1
And if n turns out to be even,
Number of images= n-1 for all positions of object

Now, coming back to your question, 
Here x=50
n=360/x
  =360/50
  =7.2
Rounding off,n=7
Now,n is odd.

(1) Asymmetrically
number of images=n
                             =7
(2) Symmetrically
number of images= n-1
                            = 7-1
                            =6

I hope all your queries about this topic are solved. 

Answer 2

case 1
when the object is placed asymmetrically between two plane mirrors inclined at an angle of 50°
we know the formula of n is equal to 360 by theta
here theta is 50 degree
so n is equal to
360/50=7.2
estimating
n=7

so if the object is placed asymmetrically the number of images formed is 7

case 2
symmetrically

n is odd
so number of images formed
=7-1=6

hope it helps