An object is placed 10 centimetre from a concave mirror the focal length is 5 cm determine (a) The image distance (b) the magnification of image
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Answer:
a) 10 cm.
b) 1
Explanation:
It can be done by the mirror formula
v = image dist. = ?
u = obj. Dist. = 10 cm
f = focal length = 5cm
1/f= 1/v + 1/u
1/v = 1/f - 1/u
1/v = 1/5 - 1/10
1/ v = 2/10-1/10
1/v = 1/10
v = 10 cm
So the image is also formed at 10 cm to the right of Pole which means the object was placed at the centre of curvature.
The magnification of the image = v/u = 10/10 = 1
So the image formed is of the same size as the object.
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Answered by
1
image distance=10
magnification =1
hope the answer helps
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