Question

An object is placed 15cm from a concave mirror of radius of curvature 60 cm. Find the position of the image and its magnification?

Answer 1

Your answer is --

Given, u = -15cm and R = -60cm

we know that

focal length f = R/2 = -60/2 = -30cm

Now,

according to mirror formula

➡ 1/v + 1/u = 1/f

=> 1/v = 1/f - 1/u

=> 1/v = -1/30 + 1/15

=> 1/v = -1+2 /30

=> 1/v = 1/30

=> v = 30 cm

therefore , image is 30cm from the mirror and + sign show that image is virtual and erect .

Now,

➡ Magnification m = -v/u

=> m = -30/-15

=> m = 2

Hence, magnification of m is 2

♡──━━━━━━⊱✿⊰━━━━━━──♡

$\huge \pink{✿} \red {C} \green {u} \blue {t} \orange {e} \pink {/} \red {Q} \blue {u} \pink {e} \red {e} \green {n} \pink {♡}$

Answer 2

$\huge{\fcolorbox{purple}{pink}{\fcolorbox{yellow}{red}{\bf{\color{white}{ᴀɴsᴡᴇʀ}}}}}$

.

.

.

focal length f= R/2 = -60/2 = -30cm

Now,

according to mirror formula

1/v + 1/u = 1/f

=> 1/v = 1/f-1/u

=> 1/v = -1/30 + 1/15

=> 1/v = -1+2 /30

=> 1/v = 1/30

=> y = 30 cm

therefore, image is 30cm from the mirror and + sign show that image is virtual and erect.

Now,

➡ Magnification m = : -v/u

=> m = -30/-15

=> m = 2

Hence,

Magnification is equals to 2.

.

.

.

Hope it's helpful to you ☺️♥️