Question

An object is placed 5cm in front of a concave mirror of focal length 10cm. Find the position, nature and magnification of the image​

Answer 1

Answer:

position=5cm from mirror.

nature=virtual,erect

magnification=enlarge image

Answer 2

Answer:

An object is placed $5cm$ in front of a concave mirror of focal length $10cm$. The position of the image $v=10cm$ and magnification of the image​ is $2$. The image is enlarged, virtual, and erect.

Explanation:

We have a mirror equation that relates the object distance ($u$), the image distance ($v$), and the focal length of the mirror ($f$) as follows

$1/v+1/u=1/f$

from the question object distance is $u=-5cm$, and the focal length is $f=-10cm$

(distance against the incident light is taken as negative by sign convention)

substitute the values to get image distance $1/v=-1/10+1/5=1/10$

$v=10cm$

The magnification is the ratio of the height of the image to that of the object,

$m=-(\frac{v}{u} )$ $=-(10/-5)=2$

When the object is in-between focal length and mirror nature of the image is enlarged, virtual, and erect.