Physics, asked by kavyanshvineetasharm, 8 months ago

Calculate the equivalent height of a water barometer, if the pressure recorded by mercury barometer is 60 cm of mercury. (Density of mercury is 13600 kgm−3 and density of water is 1000 kgm−3 ).

Answers

Answered by Anonymous
4

Answer:

Height of the Mercury Column in a Barometer = 75 cm.

For Finding the Pressure in S.I. System, Changing 75 cm into meter.

∴ Height of the Mercury column(h) = 75 cm.

= 0.75 m.

Acceleration due to gravity(g) = 9.8m/s

2

Density of the Water =10

3

kg/m

3

.

=1000kg/m

3

Specific Gravity of the Mercury = 13.6

Specific Gravity of the Substance is the Ratio of the Density of the Substance to the Density of the Water.

∴ Specific Gravity = Density of the Substance /Density of the Water.

⇒ Density of the Mercury(ρ) = 1.3×1000

= 1300kg/m

3

.

Now,

Using the Formula,

Pressure(P) = hρg

= 0.75×1300×9.8

= 9555 Pa.

Hence, the Pressure is 9555 Pa.

For Finding the Pressure in C.G.S. System,

Height of the Mercury Column(h) = 75 cm.

Acceleration due to gravity(g) = 9.8m/s

2

=9.8×100cm/s

2

=980cm/s

2

.

Density of the Water =1000kg/m

3

.

= 1000×10

6

g/10

6

cm

3

.

= 10

6

/10

6

g/cm

3

.

= 1g/cm

3

∴ Density of the Mercury(ρ) = Specific Gravity of the Mercury × Density of the Water.

=1.3×1

=1.3g/cm

3

.

Now Using the Formula,

Pressure(P)= hρg

= 75×1.3×980

= 9550 Ba.

Hence the Pressure is 9550 barye.

Answered by suzie4
2

Answer:

hMghH2O=dH2OdMg

0.6hH2O=100013600

∴hH2O=100013600×0.6=8.16m

=816cm

Explanation:

=816cm

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