Question

an object is placed at 10 cm in front of concave mirror of radius of curvature 15 cm find the position nature and magnification of the image

Answer 1

please mark it as brainlist if you like.

Answer 2

The position nature and magnification of the image is -3.

What is concave mirror?

• A concave mirror has a reflective surface that is curved inward and away from the light source.
• Concave mirrors reflect light inward to one focal point. Unlike convex mirrors, the image formed by a concave mirror shows different image types depending on the distance between the object and the mirror.

What does focal length mean?

• The focal length of a lens is determined when the lens is focused at infinity.
• Lens focal length tells us the angle of view—how much of the scene will be captured and the magnification how large individual elements will be.
• The longer the focal length, the narrower the angle of view and the higher the magnification.

According to the question:

In concave mirror, using sign convention

$\\ \mathrm{u}=-10 \mathrm{~cm} \\ \mathrm{R}=-15 \mathrm{~cm} \\ \mathrm{f}=\frac{-15}{2} \mathrm{~cm}$

Using mirror’s relation

$\frac{1}{\mathrm{v}}+\frac{1}{\mathrm{u}}=\frac{1}{\mathrm{f}} \\ \frac{1}{\mathrm{v}}=\frac{1}{\mathrm{f}}-\frac{1}{\mathrm{u}} \\ \frac{1}{\mathrm{v}}=-\frac{2}{15}+\frac{1}{10} \\ \frac{1}{\mathrm{v}}=\frac{-1}{30} \\ \mathrm{v}=-30 \mathrm{~cm}$

Image is real and it forms at a distance of 30 cm in front of mirror.

Magnification

$\mathrm{m}=\frac{-\mathrm{v}}{\mathrm{u}} \\ \mathrm{m}=\frac{30}{-10}=-3$

Hence, The image's position and magnification are both -3.

Learn more about focal length here,

https://brainly.in/question/2066166?msp_poc_exp=5

#SPJ2