Can any one answer the 47 th question with diagram
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Given AD=DE -eq(1)
Area of triangle ABC =1/2*base*height
=1/2*BC*AD - eq(2)
Area of triangle BCE
=1/2*base*height
=1'2*BC*DE
=1/2*BC*AD-eq(3) [from eq(1)]
From eq(2)and(3)
Area of (ABC) =Area of (BCE)
Area of triangle ABC =1/2*base*height
=1/2*BC*AD - eq(2)
Area of triangle BCE
=1/2*base*height
=1'2*BC*DE
=1/2*BC*AD-eq(3) [from eq(1)]
From eq(2)and(3)
Area of (ABC) =Area of (BCE)
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Cherry010:
read the 47th question properly
U tell what's right
me
Haa u
I don't know so I have asked
bit I think it's not the perfect diagram
Hoo then leave it
ok
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