Question

Can any one answer the 47 th question with diagram

Answer 1

Given AD=DE -eq(1)
Area of triangle ABC =1/2*base*height
=1/2*BC*AD - eq(2)
Area of triangle BCE
=1/2*base*height
=1'2*BC*DE
=1/2*BC*AD-eq(3) [from eq(1)]
From eq(2)and(3)
Area of (ABC) =Area of (BCE)