Question

an object is placed at 15cm ifront of concave mirror of radius of curvature 25c m . find the magnification produced by mirror .also write the nature of the image?

Answer 1

u = -15cm
f = c/2
f = -25/2cm. or -12.5cm
1/f = 1/v + 1/u
1/v = 1/f - 1/u
1/v = -2/25 - (-1/15)
1/v = -6+5/75
1/v = -1/75
v = -75cm
m = -v/u
m= 75/-15
m = -5
image formed - larger than the size of object, at the same side where the object is placed, beyond c and real and inverted

Answer 2

Hey,
Given,u=15cm
radius =25,so focal length =25/2=12.5
Now,
Since it is a concave mirror therefore,
u=-15 and f=-12.5
Applying the formula,
1/f=1/u+1/v
1/-12.5=1/-15+1/v
On solving,
v=-75cm.
So,
m=-v/u
= -(-75/-15)
=-5.
Hope this helps you buddy!!

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