an object is placed at 35 cm from a concave mirror of focal length 70 cm. determine the position and nature of image formed.
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for concave mirror object distance (u) = -35 cm
focal length(f) = -70 cm
mirror formula 1/v+1/u= 1/f
1/v = 1/f -1/u
1/v = - 1/70 -(-1/35)
= - 1/70+1/35
1/v = 1/70
v = 70 cm back of the mirror
magnification = - v/u = -70/-35 = +2 so image will be enlarged.virtual and errect behind the mirror
focal length(f) = -70 cm
mirror formula 1/v+1/u= 1/f
1/v = 1/f -1/u
1/v = - 1/70 -(-1/35)
= - 1/70+1/35
1/v = 1/70
v = 70 cm back of the mirror
magnification = - v/u = -70/-35 = +2 so image will be enlarged.virtual and errect behind the mirror
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