Question

Chemistry...Doubt....Please Help me out.

Answer 1

HELLO USER,

Here's your answer:

Reaction: H₂ + Cl₂ ----> 2HCl

Volume ratio = 1 : 1 : 2
(1 volume of H₂, 1 volume of Cl₂ and 2 volumes of HCl)



Given that, 4cm³ of Hydrogen is unreacted.

So, volume of reacted mixture = (36 - 4) cm³ = 32 cm³


Now, 1 volume of H₂ = 

$\frac{1}{2} \times 32 = 16cm^{3}$

Again, 1 volume of Cl₂ =

$\frac{1}{2} \times 32 = 16cm^{3}$


Actual volume of Hydrogen given at first = (16 + 4) cm³ = 20 cm³


Hence, original composition of the mixture was, 20cm³ of Hydrogen and 16 cm³ of Chlorine.




Hope my answer is satisfactory...
THANKS!

Answer 2

Hii friend,

➡Equation :-

H2 + 2Cl = 2 HCl ( hydrogenchloride)

➡Explanation :-

From this equation , we see 1 mol H2 reacts with 1mol Cl2 and it forms 2HCl.

So, H2 and Cl2 reacts with equal volume according to the Avogadro's Law.

If you have 4cm^3 H2 left , then volume of gases reacting 16 cm^3 H2 and 16 cm^3 Cl2 due to 1 : 1 ratio.

Thus , at the start there was 16 cm^3 + 4 cm^3 = 20 cm^3 of H2 and 16 cm^3 of Cl2...i hope it helps you


Mark me as a brainliest....✌