Question

An object is placed at 45 cm in front of converging mirror of radius of curvation 30cm. At what distance the image would be formed. Mention the nature of the image

QUALITY ANSWERS NEEDED ​

Answer 1

Step-by-step explanation:

In a concave mirror, we have :-

→ u = -45 cm

→ f = -15 cm

According to mirror formula :-

1/v = 1/u = 1/f

⇒ 1/v = 1/f - 1/u

⇒ 1/v = (1/-15) - (1/-45)

⇒ 1/v = (-1/15) - (-1/45)

⇒ 1/v = -2/45

⇒ 45 = -2v

⇒ v = 45/-2

⇒ v = -22.5 cm

Answer 2

Answer:

Heya Here's the required Answer mate

In a concave mirror, we have :

• → u = -45 cm

• → f = -15 cm

According to mirror formula :

• 1/v = 1/u - 1/f

• → 1/v = 1/f-1/u

• ⇒ 1/v = (1/-15) - (1/-45)

• ⇒ 1/v = (-1/15) - (-1/45)

• → 1/v = -2/45

• → 45 = -2v

• ⇒ v = 45/-2

• → v = -22.5 cm

Therefore the image will formed at 22.5cm on the left of the mirror

Hope it helps