an object is placed at 4cm from a concave mirror of radius 24cm . find position of image.is the image magnified
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In the given question,
Object distance u = -4cm ( using sign convention )
Radius of curvature = 24 cm
Focal length = 1/2 R
f = 1/2×24
focal length = -12cm ( sign convention )
By mirror formula ,
1/f = 1/u + 1/v
1/-12 = 1/-4 + 1/v
1/-12 = v - 4 / -4v
-4v / -12 = v - 4
2v / 6 = v - 4
2v /6 - v = -4
-4v / 6 = -4
v = 6cm
Position of the image is 6cm.
Yes the image is magnified.
Object distance u = -4cm ( using sign convention )
Radius of curvature = 24 cm
Focal length = 1/2 R
f = 1/2×24
focal length = -12cm ( sign convention )
By mirror formula ,
1/f = 1/u + 1/v
1/-12 = 1/-4 + 1/v
1/-12 = v - 4 / -4v
-4v / -12 = v - 4
2v / 6 = v - 4
2v /6 - v = -4
-4v / 6 = -4
v = 6cm
Position of the image is 6cm.
Yes the image is magnified.
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