An object is placed at a distance 10cm from a lens of power 4D. find position and nature of image
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1
here
u = -10 cm
f = 100/P cm = -100/4 cm = -25 cm
the image distance can be calculated using the following relation
1/f = 1/v - 1/u
or
1/v = 1/f +1/u
or
1/v = -1/25 - 1/10
or
the image distance is
v = 7.14 cm
u = -10 cm
f = 100/P cm = -100/4 cm = -25 cm
the image distance can be calculated using the following relation
1/f = 1/v - 1/u
or
1/v = 1/f +1/u
or
1/v = -1/25 - 1/10
or
the image distance is
v = 7.14 cm
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