Question

An object is placed at a distance 20 cm,in rarer medium,from the pole of convex refracting spherical surface of radius of curvature 10cm.if the refractive index of the rarer medium is 1 and of the refracting medium is 2 then the position of image is at​

Answer 1

40 Cm From the Pole and Inside the denser Medium....

Answer 2

The position of the image is at a distance of 5 cm from the pole of the convex refracting spherical surface.

Given,

D = 20cm,

radius of curvature = 10cm.

To find,

Position of image.

Solution,

To determine the position of the image, you can use the lens equation:

1/di + 1/do = 1/f

Where,

'di' = distance from the object to the lens,

'do' = distance from the image to the lens,

and focal length of the lens = 'f'

The distance from the object to the lens is 20 cm, the refractive index of the rarer medium is 1, and the radius of curvature of the lens is 10 cm, so the focal length of the lens is f = 10 cm / (2-1) = 10 cm.

Plugging these values into the lens equation, we get:

1/20 cm + 1/do = 1/10 cm

Solving for do, we find that the distance from the image to the lens is do = 5 cm.

Therefore, the position of the image is at a distance of 5 cm from the pole of the convex refracting spherical surface.

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